(1/(x^2-7)-4)^3

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Solution for (1/(x^2-7)-4)^3 equation: 


D( x )

x^2-7 = 0

x^2-7 = 0

x^2-7 = 0

1*x^2 = 7 // : 1

x^2 = 7

x^2 = 7 // ^ 1/2

abs(x) = 7^(1/2)

x = 7^(1/2) or x = -7^(1/2)

x in (-oo:-7^(1/2)) U (-7^(1/2):7^(1/2)) U (7^(1/2):+oo)

(1/(x^2-7)-4)^3 = 0

1/(x^2-7)-4 = 0

1/(x^2-7)+(-4*(x^2-7))/(x^2-7) = 0

1-4*(x^2-7) = 0

29-4*x^2 = 0

(29-4*x^2)/(x^2-7) = 0

(29-4*x^2)/(x^2-7) = 0 // * x^2-7

29-4*x^2 = 0

(29-4*x^2)^3 = 0

-4*x^2 = -29 // : -4

x^2 = 29/4

x^2 = 29/4 // ^ 1/2

abs(x) = (29/4)^(1/2)

x = (29/4)^(1/2) or x = -(29/4)^(1/2)

x in { (29/4)^(1/2), -(29/4)^(1/2), (29/4)^(1/2), -(29/4)^(1/2), (29/4)^(1/2), -(29/4)^(1/2) }

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